Question

At present the product of the ages of a mother and her daughter is 100
Ten years later, mother's age will be twice that of her daughter. Find
their present ages.

Answer 1

Answer:

take as X of there present ages

Answer 2

Step-by-step explanation:

The product ages of mother and daughter is 100

Let the age of mother = x

Then the daughter=100/x

Ten years later the age of mother=x+10

Ten years later the age of daughter=100/x+10

As per problem

The age of mother ten years later = Twice of daughter age ten years later

x+10 = 2(100/x+10)

x+10 =2(100+10x/x)

x+10 =200+20x/x

x(x+10) =200+20x

x2+10x=200+20x

x2+10x-20x =200

x2-10x=200