Math, asked by rishavroygopal, 4 months ago

At present the ratio of ages of son and his father is 2:7 , 6 years ago it was 1:6 . after 4 years the ratio will be​

Answers

Answered by TheBrainliestUser
45

Answer:

After 4 years the ratio will be 8 : 23

Step-by-step explanation:

Let the present ages of son and his father be 2x and 7x respectively.

6 years ago:

Son's age = (2x - 6) years

Father's age = (7x - 6) years

According to question:

(2x - 6)/(7x - 6) = 1/6

→ 6(2x - 6) = 1(7x - 6)

→ 12x - 36 = 7x - 6

→ 12x - 7x = - 6 + 36

→ 5x = 30

→ x = 6

Present ages of:

Son = 2x = 2 × 6 = 12 years

Father = 7x = 7 × 6 = 42 years

Ratio of their ages after 4 years:

= (12 + 4) / (42 + 4)

= 16 / 46

= 8 / 23 = 8 : 23


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Answered by Anonymous
39

Answer:

Solution :-

let the age of son and father be 2y and 7y

2y - 6/7y - 6 = 1:6

6(2y - 6) = 1(7y - 6)

12y - 36 = 7y - 6

12y - 7y = 36 - 6

5y = 30

y = 6

Father = 7y = 7(6) = 42 years

Son = 2y = 2(6) = 12 years

After 4 years

42 + 4/12 + 4

46/16

8/23

Required Ratio :-

 \large \sf \: 8 : 23


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