Math, asked by kanhaiyaray4897, 11 months ago

At present the ratio of the ages of A to B is 3:8 and that of A to C is 1:4. Three years ago , the sum of the ages of A, B & C was 83 years. What is the present age (in years) of C ? {

Answers

Answered by mhanifa
0

Answer:

48

Step-by-step explanation:

1. A/B=3/8 => 8A=3B

2. A/C=1/4 => 4A=C

3. A+B+C-3*3=83 => A+B+C=92

From 1 & 2 we get:

4A=C => A=C/4

2C=3B => B=2C/3

Now:

A+B+C=92

C/4+2C/3+C=92

C*(1/4+2/3+1)=92

C=48

A=12

B=32

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