Question

at present , the sum of ages of ruby and her daughter is 49. seven years ago ruby was six times as old as her daughter . find their present ages

Answer 1

let
age of ruby=x
age of her daughter=y
SEVEN YEARS AGO
ruby=x-7
her daughter's age= y-7
ruby age= 6(y-7)
x-7=6(y-7)

SUM OF THEIR AGES=49

ruby age + daughter age=49
6(y-7)+ (y-7)=49
6y - 42 + y -7=49
8y - 49-7=49
8y = 2×49
y=98 / 8
y=12 years 3 months