Math, asked by Priyadharshini15, 1 year ago

at present wasim age is more than the square of her son zayn age when zayn his fathers present age wasim age would be sixteen years more than 10 times of the present age find the present age of both wasim and zayn

Answers

Answered by assalterente
0

Answer:

Zayn is 6 and Wasim is 41.

Step-by-step explanation:

Let x be Zayn's present age. Then present age of Wasim is x² + 5

Zayn becomes his father's age in x² + 5 - x years.

Then Wasim's age will be x² + 5 + x² + 5 - x = 2x² - x + 10

Given, when zayn his fathers present age, wasim age would be sixteen years more than 10 times of the present age, this means:

2x² - x + 10 = 10x + 16

⇒ 2x² - 11x - 6 =0

⇒ (2x+1)(x-6)=0

⇒ x = -\frac{1}{2} or x = 6

Age is a positive number, then:

⇒ x = 6

Wasim's age:

x² + 5 = 36 + 5 = 41

Hence, present age of Zayn is 6 and present age of Wasim is 41

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