Question

At present Wasim's age is 5 more than the square of his son Zyan's age. When Zyan grows to his father's present age, Wasim's age would be sixteen years more than 10 times the present of Zyan.
Find the present ages of both Wasim and Zyan

Answer 1

in present

according to question

son zyan age=x

father wasim age=5+x^ (because was in age is 5 more then the square of his son age)

and

when

zyan grows to his father present age,

zyan age=10 (x)

wasim age =16+10 (x) (epln-wasim age would be 16yr more then 10time zyan PRESENT age)

so

zyan present age

5+x^ =16+10x

x^ -10x-11=0

here we got= x (x+1)-11 (x+1)

(x+1)(x-11)=0

x= -1,11

age is not negative value so

x=11

zyan age=11

wasim age =126