Question

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Q.12 An elavator decends into a mine shaft
the rate of 6 m/min. If the decent starts
from 10m above the ground level, how long
it take to reach 350 Level.​

Answer 1

Answer:

☺✨That is your answer ✨☺

Answer 2

Answer:

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360m = ( - 360)/(-6) [from the formula : speed= distance/time]

=60 minutes.(ans)

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