At r the dimensions of cuboid whose volume is x-2 into ×-3 into ×-5 where x is greater than 5
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Answer:
length >3
Width >2
and Height >0
Step-by-step explanation:
Given That volume =(x-2)(x-3)(x-5)=LxWxH
such that x>5
so
if we consider the Dimensions as
Length =(x-2)
width=(x-3)
and height=(x-5)
applying the condition x>5
We get x-2>5-2 ===>x-2>3, hence length >3
x-3>5-3 ====> x-3>2, hence width >2
and height =x-5>5-5 ===>x-5>0
so height >0
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