Physics, asked by yugal8703, 6 months ago

At resonance , the L. C. R circuit is

Answers

Answered by samjoshua22634
0

Answer: current flowing through a series resonance circuit is the product of voltage divided by impedance, at resonance the impedance, Z is at its minimum value, ( =R ). Therefore, the circuit current at this frequency will be at its maximum value of V/R

Explanation:

Answered by nagavardhanpotluri1
0

Answer:

Imax=Vrms/R

Explanation:The resonance of a series LCR circuit occurs when the inductive and capacitive reactances are equal in magnitude but cancel each other because they are 180 degrees apart in phase.

In LCR circuit, the impedance is given by:

Z=R2+(XL​−XC​)2

where R is resistance, XL​ is inductive resistance and XC​ is capacitive resistance.

At Resonance in LCR circuit,

XL​=XC​

ωL=ωC1​

∴ω=LC

​1​ which is known as resonance frequency.

Further, impedance is minimum at resonance, Zmin​=R which means that the current becomes maximum, Imax​=RVrms​​.

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