Question

At room temperature (27°C) the rms' speed of the
molecules of a certain diatomic gas is found to be
1920ms! The gas is
(A) H
(B) F2
(C) O2
(D) C12​

Answer 1

Speed is supposed to be the rms speed , given by v=

2

M

3RT

, Where R is gas constant.

Given that T=27+273=300Kelvin, R=8.31J/Kelvin and v=1920m/s putting all these to the expression,

we get M=.02 i.e. Molar weight is .02gm/mole

(C) O2

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