Chemistry, asked by Shobhit9634, 8 months ago

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea = 60 g mol⁻¹)
(A) 0.027 mmHg (B) 0.031 mmHg
(C) 0.028 mmHg (D) 0.017 mmHg

Answers

Answered by Anonymous
1

Answer:

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea = 60 g mol⁻¹)

(A) 0.027 mmHg (B) 0.031 mmHg

(C) 0.028 mmHg

(D) 0.017 mmHg✓✓

Answered by AbdJr10
0

Answer:

D. will be correct answers

Explanation:

hope the answer will help you

Attachments:
Similar questions