At room temperature of 25°C The barrier potential for
silicon is 0.7V. its value at 125°C will be
Answers
Explanation:
answer is 0.9 i think it is right
Answer:
The barrier potential of silicon at 125 °C is approximately 0.93V.
Explanation:
As the temperature of a semiconductor material like silicon increases, the energy level of its atoms and electrons also increase. This increase in energy causes more electrons to break free from their covalent bonds, leading to an increase in the number of free charge carriers in the material.
The increase in free charge carriers reduces the width of the depletion region, which in turn reduces the barrier potential. The relationship between the barrier potential and temperature is described by the equation:
Vt = V0 - (αT)
Where Vt is the barrier potential at temperature T, V0 is the barrier potential at a reference temperature (25°C in this case), and α is the temperature coefficient of the barrier potential.
For silicon, the temperature coefficient α is approximately -2.3 mV/°C. Using this value, we can calculate the barrier potential at 125°C as follows:
Vt = V0 - (αT)
Vt = 0.7V - (-2.3 mV/°C x 100°C)
Vt = 0.7V + 230 mV
Vt = 0.93V
Therefore, When, the barrier potential of silicon is 0.7V, at room temperature, so at 125°C The barrier potential will be approximately 0.93V.
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