Chemistry, asked by khansa166, 8 months ago

At room temperature, the mole fraction of a solute
is 0.2 and the vapour pressure of the pure solvent
is 0.80 atm. Then the lowering of vapour pressure is
(1) 0.16
(2) 0.6
(3) 0.20
(4) 0.80​

Answers

Answered by rameshhoney31
2

YOUR ANSWER IS :

  • 0.16

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