Question

at s.t.p find the volume and no. of atoms when 6gr of coal is burnt in the presence of Oxygen.

Answer 1

PV=nRT⇒n=PVRT

n=1atm⋅11.2L0.082(L⋅atmmol⋅K⋅293.15K)=0.4659 moles  O2

This is equivalent to having

0.4659moles⋅6.022⋅1023molecules1mole=2.81⋅1023molecules