Question

At same temperature and pressure prove that, rate of diffusion of hydrogen is four times than the oxygen

Answer 1

Given :

▪ Pressure and temperature remains constant throughout the diffusion process.

To Prove :

▪ Rate of diffusion of hydrogen is four times than the oxygen.

Concept :

☞ This question is completely based on the concept of Graham's law of diffusion.

☞ As per this law, Under similar conditions of temperature and pressure, rates of diffusion of different gases are inversely proportional to the square root of their molecular masses.

Mathematically,

R¹/R² = √M²/√M¹

where,

▪ R¹ and R² are the rates of diffusion of gas 1 and gas 2 respectively and M¹ and M² are molecular masses of gas 1 and 2 respectively.

CalculaTion :

Mol. mass of O2 (1) : 32g/mol

Mol. mass of H2 (2) : 2g/mol

→ R¹/R² = √M²/√M¹

→ R¹/R² = √2/√32

→ R¹/R² = 1/√16

→ R¹/R² = 1/4

→ R² = 4R¹

Hence Proved !!!