Question

At same temperature and pressure the volume of oxygen required for complete combustion of 20 ml of
ethene is
(1) 30 ml
(2) 60 ml
(3) 40 ml
(4) 50 ml
r​

Answer 1

Answer:

3.) 40ml is the answer dude

Answer 2

Answer:

Correct option is B.

Explanation:

C₂H₄ + 3O₂ → 2CO₂+2H₂O

At STP we have

volume of 1 mole of gas = 22400 ml

so, moles of ethene in 20 ml of volume =$\frac{1}{22400} *20=0.00089moles$

for, 1 mole of ethene we require 3 mole of oxygen

so, for 0.00089 mole of ethene we require oxygen

= 0.00089×3=0.00267 moles

hence, volume of oxygen required =0.00267×22400≈ 60ml