Question

At sea level the atmospheric pressure is 1.04×10 to the power 5 pa.Assuming g-10ms/2. density of air to be uniform and equal to 1.3 kgm/3. Find the height of the atmosphere?

Answer 1

Pressure = hdg

h = Pressure / (dg)
= (1.04 × 10^5 Pa) / (1.3 kg/m³ × 10 m/s²)
= 8000 m
= 8 kilometers

Height of the atmosphere is 8 kilometers

Answer 2

Given:

Atmospheric pressure,P=$1.04\times 10^5 Pa$

g=$10 m/s^2$

Density of air,$\rho=1.3 kg/m^3$

To find:

Height of the atmosphere

Solution:

We know that

Atmospheric pressure

$P=h\rho g$

By formula we get

$h=\frac{P}{\rho g}$

Substitute the values

$h=\frac{1.04\times 10^5}{1.3\times 10}$

$h=8000 m$

1 km=1000 m

$h=\frac{8000}{1000}=8 km$

Height of the atmosphere,h=8 km