Question

At some point along a straight line, a person A has constant velocity of 10 m/s and a person B start from rest with acceleration at 2 m/s2. What can be the maximum distance by which A can be ahead of B.(Ans 25 m) ​

Answer 1

Answer:

V²=u²+2as

Given u=0 v=10m/s a=2m/s² s=?

now

10²=0²+2*2*s

100=4s

s=100/4

=25 m

Max.Distance=25

Answer 2

Answer:

ur answer is in attachment xD