At some time of a day , the length of shadow of a tower is equal to its height .find the suns altitude at that time.
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Answered by
36
let the height of tower be x and the angle be y°..
now, tan (theta) = height / base
ATQ, height = base
tan 45°= 1, so if the angle will be 45° then
=> height / base = 1
=> height = base
that means the angle
y° = 45°
now, tan (theta) = height / base
ATQ, height = base
tan 45°= 1, so if the angle will be 45° then
=> height / base = 1
=> height = base
that means the angle
y° = 45°
AtithiRoy:
my pleasure
Answered by
44
let height of the tower = x
so , length of shadow also = x
so , tanø = perpendicular/ base
tanø = x/x
tanø = 1
tanø = tan45
so, ø = 45
hence ,sun altitude =45 ans..
so , length of shadow also = x
so , tanø = perpendicular/ base
tanø = x/x
tanø = 1
tanø = tan45
so, ø = 45
hence ,sun altitude =45 ans..
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