Question

At STP, 0.3 g of a volatile organic compound displaced 112 cc of air. what is its molecular weight of the compound?

Answer 1

Answer:

60g/mol

Explanation:

at STP , 112 cc = 0.3 GM

then, 22400 cc =( 0.3/112)×(22400)

= 60g/mol

Answer 2

Given :

mass (m) = 0.3 g

Volume occupied (V) = 112 cc

To Find :

Molecular weight of the compound

Solution :

Let 'M' be the molecular weight of the compound.

We know,

22400 ml volume at STP contains 'M' mass of the compound.

112 ml volume at STP contains $\frac{M}{22400}$×112 gm of the compound.

As per question,

            $\frac{M}{22400}$ × 112    =  0.3

⇒          M                =  60 gm

Therefore, the molecular weight of the compound is 60 gm.