Question

At STP 11.2 L of an unknown gas weighs 15 g.
Unknown gas may be
(1) NO,
(2) C2H6
(3) CO₂
(4) C2H2​

Answer 1

Answer:

C2h6

Explanation:

at stp vol of a gas is 22.4 l

vol is halved so mass is also halved

15*2=30

mass of c2h6 is 30

Answer 2

Answer:

The STP should be calculated in 22.4 lit so it should be multiplied by 2, then 30gms should be there.CO2 is 12+8(2)=30gms.So CO2 Is the correct answer