Question

At stp 16 ml of o2 diffuse through a porous partition in t seconds. what volume of co2 will diffuse in the same time and under same conditions

Answer 1

Answer:

The volume of CO₂ is 13.651 ml, that will diffuse at the same time and under same conditions.

Explanation:

Given Data:  

At STP,

Volume of O₂, V1 = 16 ml

Both O₂ & CO₂ diffuse at same time i.e., t1 = t2 = t seconds

To find: Volume of CO2, V2

Let rate of diffusion of O₂ be “R1” and CO₂ be “R2”

Rate of diffusion of a gas = Volume / time

Also, let the molar mass of O2 be “M1” = 31.998 g/mol and the molar mass of CO2 be “M2” = 44.01 g/mol

By using Graham’s Law, we have

R1 / R2 = √[M2 / M1]

∴ [V1/t] / [V2/t] = √[M2 / M1]

Or, 16 / V2 = √[44.01 / 31.998]

Or, 16 / V2 = 1.172

Or, V2 = 13.651 ml

Hope this is helpful!!!

Answer 2

Answer:

the answer was 13.65

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