at stp 16ml of O2 is diffused through porous partition in t seconds. what volume of CO2 will be diffused in the same time and condition?
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Answered by
7
Thanks for this question. Please find the answer below:
At stp 16ml of HO₂ is diffused through porous partition in t seconds. 18.76ml of CO₂ will be diffused in the same time and condition.
This can be calculated under the Graham's Law of Diffusion of Gases. According to the law, rate of diffusion is inversely proportional to molar mass of the gas.
Answered by
47
This is a question on Graham's law of diffusion.
The formulae is as follows :
RO₂/RCO₂ = √mmCO₂/mmO₂
Molecular mass of CO₂ = 12 + 32 = 44
Molecular mass of O₂ = 32
Doing the substitution we have :
16/R = √44/32
16/R = √1.375
16/R = 1.1726
16 = 1.1726R
R = 16/1.1726
R = 13.64
= 13.64 ml
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