At STP , 2.24 L is occupied by
(a) 4.4g CO2. (b) 0.64 g SO2
(c) 28g CO. (d) 16 g O2
[ C=12, O=16, S=32
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one mole of a gas at STP occupies 22.4L. Then how many moles of gas occupy 2.24 L. So 2.24/22.4 moles of the gas occupy 2.24 L at STP. Hence 0.1 moles of a gas occupies 22.4 L. Find the number of moles in all parts
(a) No. of moles present in 4.4g CO2 (2×16+12) =>4.4/44 =>0.1
(b) No. of moles present in 0.64g SO2 (32+2×16) => 0.64/64 =>0.01
(c) No. of moles present in 28 g of CO(12+16) => 28/28 => 1.
(d) 16g O2 => 16/32 =>0.5 moles. Hence the correct answer is option(a). Hope it helps you.
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