Question

At stp (273 k and 100 kpa), 1.15 dm3 of a gas has a mass of 3.96 g. Determine the molar mass of the gas.

Answer 1

At stp (273 k and 100 kpa), 1.15 dm3 of a gas has a mass of 3.96 g. Determine the molar mass of the gas.

The density of a gas is measured at 1.853 g / L at 745.5 mmHg and 23.8 °C.

Answer 2

The molar mass of the gas is 79 g/mol

Explanation:

To calculate the molar mass of gas, we use the equation given by ideal gas equation:

$PV=nRT$

Number of moles (n) can be written as: $n=\frac{m}{M}$

where, m = given mass

M = molar mass

$PV=\frac{m}{M}RT}$

where,

M = molar mass = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = 273K

P = pressure of the gas = 100kPa = 0.98 atm      1kPa= 0.0098atm

V= Volume of gas =$1.15dm^3=1.15L$

Putting values in equation

$0.98\times 1.15=\frac{3.96g}{M}\times 0.0821\times 273K$

$M=79g/mol$

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