at STP 36.9 litre of a certain gas weighs 88.96 gram what is the density of this gas at 20 degree Celsius and 555 mm
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Here’s how you go about this. Let’s look at the ideal gas law.
pV=nRTpV=nRT
What is missing is the number of moles of gas, BUT you know that at STP, 1 mole of ideal gas occupies 22.4L. Thus, we have n = 36.9/22.4 = 1.64 as the number of moles.
Now, rearrange the ideal gas law to give the volume at the new p and T,
V=nRT/pV=nRT/p
then find the density by taking the original mass (88.96g) and dividing that by the new volume.
plz mark this question As brainlist
pV=nRTpV=nRT
What is missing is the number of moles of gas, BUT you know that at STP, 1 mole of ideal gas occupies 22.4L. Thus, we have n = 36.9/22.4 = 1.64 as the number of moles.
Now, rearrange the ideal gas law to give the volume at the new p and T,
V=nRT/pV=nRT/p
then find the density by taking the original mass (88.96g) and dividing that by the new volume.
plz mark this question As brainlist
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