Question

at STP,a container has 1 mole of He ,2 mole of Ne,3 mole O2 ang 4 mole of N2.without changing total pressure if 2mole of O2 is removed.the partial pressure of O2 will be decreases by​

Answer 1

Answer:

Correct option is

C

58.33%

PO2=103×PT

After removing 2 mole of O2,

PO2′=81×PT

Decrease in partial pressure of O2=103PT103PT−8PT×100 

                                                               =58.33%