Question

At STP, The volume occupied by 11g of Carbon dioxide

Answer 1

Hey there!

We know that,
At STP ( Standard temperature and pressure) One mole of any gas occupies 22.4litres of volume.

Now, One mole of Carbon dioxide = 44g of Carbon dioxide.

We can relate it as,

1 mole of co2 --- 44g of co2 --- 22.4 litres.

Now, Given Atomic mass = 11g .

Let the volume occupied by 11g = x.

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We have,

44g ----- 22.4 L
11g ------- x L

Now, 44x = 22.4 * 11

x = 22.4 / 4

x = 5.6 L.

Therefore, At STP, 11 g of Carbon dioxide occupies 5.6litres of volume.

Answer 2

molar mass of carbon dioxide (co2) = 12+16*2 = 44
moles of co2 = given mass /molar mass = 11/44 = 1/4
volume of a gas at STP(0°c temp and 1 ATM pressure ) = n*22.4
where n = no. of moles
thus volume = 22.4/4 = 5.6 litre