Question

At stp volume occupied by 11.2 grams of a gas of vapour density 11.2 in litres will be:

Answer 1

Explanation:

no. of moles = mass/ molar mass

As we know, Molar mass =2* vapour density

= 2* 11.2 g/mol

no. pf moles = 11.2/2*11.2

= 1/2 mol

Volume occupied by 1 mol gas at STP = 22.4 L

Volume occupied by 1/2 mol = 22.4/2 =11.2 L

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