Question

At stp what is the mass of 448cm3 of carbon dioxide

Answer 1

22 gr co2(1 mole) occupied 22.4 liter

then,___________gr of co2 occupied 448cm^3/liters

then we do cross multiplication

__________gr of co2=(22*448)/22.4

=440 gr.

I hope this is helps to you

Answer 2

Answer:

0.88

Explanation:

stp= 22.4 dm^3

1 dm^3 - 1000cm^3

22.4 dm^3=22400 cm^3 cross multiply

mol vol

1  - 22400

x - 448

x multiplied by 22400 = 448

x= 448/22400 = 0.02 mol

find mass of CO2 = 44

mol mass

1 - 44

0.02 - x

44 multiplied by 0.02 = 0.88

Answer = 0.88