Question

at stp what will be the volume of 3.011*10^23 molecules of h2

Answer 1

1 mole has 6.022×10^23 molecules

X moles have 3.011×10^23 molecules

X=0.5

1 mole occupies 22.4 L at STP

So 0.5 miles will occupy 11.2 L at STP

Volume occupied = 11.2L

Answer 2

Answer: 11.2 Liters

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's Number}}=\frac{3.011\times 10^{23}}{6.023\times 10^{23}}=0.5moles$

1 mole of $H_2$ occupy = 22.4 L at STP

Thus 0.5 of $H_2$ occupy =$\frac{22.4}{1}\times 0.5=11.2L$

Thus the volume of $3.011\times 10^{23}$ molecules of $H_2$ occupy 11.2 L at STP.