Question

at STP ,what will be the volume of 6.022*10^23 molecules of H2

Answer 1

Answer:

any gas at STP, 6.022*10^23 molecules(or one mole) has volume of 22.4L

Answer 2

22.4 litre

Explanation:

By STP we mean

P= 1 bar

T= 273.15 K

For an ideal gas

PV = nRT

R= 8.314 Lbar K⁻¹ mol⁻¹

6.023×$10^{23}$ molecules makes 1 mole

n = 1

V = 22.4 L.

NOTE: 1 MOLE OF ANY GAS AT STP OCCUPIES 22.4 L.