Math, asked by jayeshbohra2748, 9 months ago

At sunrise the temperature was -15 degree c .by midday it increased by 45 degree c. By evening ,it fell to a third of the existing temperature and by night .a decrease of another 25 degree was observed .what was the temperature at night?

Answers

Answered by ItsHound
1

Answer:

Considering 25 degree to be 25 degree C, the answer is -15 degree C according to my calculations.

Answered by tanush29gupta
1

Answer:

-15*c

Step-by-step explanation:

since , at the morning the temperature was -15*c and by the midday the temperature increased by 45* c , i.e.( -15) *c + 45* c = 30 *c

therefore, the temperature during the mid day was 30*c .

by the evening the temperature fell to 1/3 rd of the existing temperatue . i.e 1/3 of 30* c

there fore , the temperature in the evening fell to 10 * c

and by the night the temperature decreased by another 25 degrees , thus ,10*- 25 * c = - 15 *c

therefore , the temperature at night was - 15* c

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