Math, asked by nainasaini1704, 10 months ago

at sunrise yhe temperature outside was -15 degree c.by midday the temperature increased by 45 degree c .by evening,it fell to a third of the existing temperature and by night,a decrease of another 25 degree c was found .what was the temperature at night​?

Answers

Answered by sheenRahman
25

Answer:

- 15 * c

Step-by-step explanation:

since , at the morning the temperature was -15*c and by the midday the temperature increased by 45* c , i.e.( -15) *c + 45* c = 30 *c

therefore, the temperature during the mid day was 30*c .

by the evening the temperature fell to 1/3 rd of the existing temperatue . i.e 1/3 of 30* c

there fore , the temperature in the evening fell to 10 * c

and by the night the temperature decreased by another 25 degrees , thus ,10*- 25 * c = - 15 *c

therefore , the temperature at night was - 15* c

Answered by guptaavantika290
3

Hello friends

Hope this will help you .

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