Question

At t=0 a particle at the origin has a velocity of 15m/s at 37° above the horizontal axis. At t=5 it is x=20m and y=35m

Answer 1

Answer:

Explanation:

this is a vector problem

so,

Theta = 37 degrees.

then when you create a graph of the particles’ position it is at (20,35)

Hence hypotenuse is 20 ^2 + 35^2 root.

= 400+ 1225=1665 root= 40.8= hypotenuse = distance travelled by the particle.

40.8 m.

the change in velocity is first 15 m/s in 5 seconds is 75 m.

velocity has reduced by 35 m in 5 seconds which is 7m/s

hence retardation of particle is (7-15)/5=8/5m/s^2

hence retardation = -1.6m/s^2.

force of particle = 20 I^+ 35J^

cos 37 = 4/5 sin 37=3/5

force = 20x 4/5+ 35x3/5

  =.      16+ 21 = 37 N

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