Question

At t=0,v=0 ,F=4t then find work done from 1-3sec​

Answer 1

Answer:

Given that,

Mass M=2kg

Displacement = x

Time t=2s

Now, the displacement is

x=

3

t

3

On differentiate

dt

dx

=

3

3t

2

dt

v=t

2

dt

Again differentiate

dt

dv

=2tdt

a=2tdt

Now, the force is

F=ma

F=2×2t

F=4t

Now, the work done is

dW=F⋅dx

dW=4t×t

2

dt

dW=4t

3

dt

Work done during t = 0 to 2 sec is found by integration

∫dW=

0

∫

2

4t

3

dt

W=[(2)

4

−0]

W=16J

Hence, the work done is 16 J

Answer 2

- 1 2 3 - 1 2 3 that

Explanation:

when when like tenses 10 second - 10 second -2 b