At t minutes before 5 p.m. time needed by the minute hand of a clock to show 5:45 p.m. was found to be 30 minutes more than t^2/4 minutes. Find t.
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t minutes before 5pm time needed to show 5:45pm is 60+t
according to question, 60+t=t^2/4-345
240+4t=t^2-1380
t^2-4t-1620=0
on solving this we get 4+80.5/2(ignoring the negative value)
we get t=42.25s
HellostudyFriend:
Your ans is wrong. It should be t + 45 and not t + 60. Then the answer will be 10 min.
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