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![31 { \frac{x \frac{ { \frac{ - .2 \sqrt[ { { {y {4 {1.}^{?} }^{?} }^{2} }^{2} }^{?} ]{?} }{?} }^{?} }{?} }{?} }^{?}](https://tex.z-dn.net/?f=31+%7B+%5Cfrac%7Bx+%5Cfrac%7B+%7B+%5Cfrac%7B+-+.2+%5Csqrt%5B+%7B+%7B+%7By+%7B4+%7B1.%7D%5E%7B%3F%7D+%7D%5E%7B%3F%7D+%7D%5E%7B2%7D+%7D%5E%7B2%7D+%7D%5E%7B%3F%7D+%5D%7B%3F%7D+%7D%7B%3F%7D+%7D%5E%7B%3F%7D+%7D%7B%3F%7D+%7D%7B%3F%7D+%7D%5E%7B%3F%7D+ "31 { \frac{x \frac{ { \frac{ - .2 \sqrt[ { { {y {4 {1.}^{?} }^{?} }^{2} }^{2} }^{?} ]{?} }{?} }^{?} }{?} }{?} }^{?}")
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Answered by
0
Answer:
R=
A
pl
=
πr
2
pl
R
′
=
π(2r)
2
p2l
=
2
R
Specific resistance will remain same as it is a material property but remember it depends on temperature.
Answered by
0
Answer:
thanks for free points ......
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