Question

At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the walkaway at the same time. Aditya walks at a speed of 6 km/hour on the walkaway, while Ravi stands still. When Aditya comes to the end of the walkaway, how far is he ahead of Ravi.

Answer 1

Answer:

Step-by-step explanation:

Speed of moving walkway :-4 km/h

Speed of aditya on moving walkway :- 6km/h + 4km/h = 10km/h = ==

= (25/9) m/s

Ravi stand still on moving walkway

So, speed of Ravi on moving walkway:- 4km/h = (10/9) m/s

Time taken by aditya to cover 500km=

Time = distance/speed

=(500×9)/25= 180sec

So in 180 sec distance covered by ravi =

Distance = speed ×time

= (10×180)/9=200m

So in 180 aditya covers 500m and ravi covers 200m

So , distance between them =

= 500-200= 300m

So, aditya is 300m far ahead of ravi

Please, mark it as brainliest answer

Answer 2

Answer:

aditya is 300m far ahead of ravi

Step-by-step explanation:

Speed of moving walkway :-4 km/h

Speed of aditya on moving walkway :- 6km/h + 4km/h = 10km/h = ==

= (25/9) m/s

Ravi stand still on moving walkway

So, speed of Ravi on moving walkway:- 4km/h = (10/9) m/s

Time taken by aditya to cover 500km=

Time = distance/speed

=(500×9)/25= 180sec

So in 180 sec distance covered by ravi =

Distance = speed ×time

= (10×180)/9=200m

So in 180 aditya covers 500m and ravi covers 200m

So , distance between them =

= 500-200= 300m

So, aditya is 300m far ahead of ravi

Please, mark it as brainliest answer