At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the walkaway at the same time. Aditya walks at a speed of 6 km/hour on the walkaway, while Ravi stands still. When Aditya comes to the end of the walkaway, how far is he ahead of Ravi.
Answers
Answer:
Step-by-step explanation:
Speed of moving walkway :-4 km/h
Speed of aditya on moving walkway :- 6km/h + 4km/h = 10km/h = ==
= (25/9) m/s
Ravi stand still on moving walkway
So, speed of Ravi on moving walkway:- 4km/h = (10/9) m/s
Time taken by aditya to cover 500km=
Time = distance/speed
=(500×9)/25= 180sec
So in 180 sec distance covered by ravi =
Distance = speed ×time
= (10×180)/9=200m
So in 180 aditya covers 500m and ravi covers 200m
So , distance between them =
= 500-200= 300m
So, aditya is 300m far ahead of ravi
Please, mark it as brainliest answer
Answer:
aditya is 300m far ahead of ravi
Step-by-step explanation:
Speed of moving walkway :-4 km/h
Speed of aditya on moving walkway :- 6km/h + 4km/h = 10km/h = ==
= (25/9) m/s
Ravi stand still on moving walkway
So, speed of Ravi on moving walkway:- 4km/h = (10/9) m/s
Time taken by aditya to cover 500km=
Time = distance/speed
=(500×9)/25= 180sec
So in 180 sec distance covered by ravi =
Distance = speed ×time
= (10×180)/9=200m
So in 180 aditya covers 500m and ravi covers 200m
So , distance between them =
= 500-200= 300m
So, aditya is 300m far ahead of ravi
Please, mark it as brainliest answer