At the beginning of a month, a factory has enough materials to make 240 tonnes of steel in a month. If 60 more tonnes of steel are to be made in that month, how long will the materials last? Is it an inverse proportion or proper proportion and How?
Answers
Answered by
0
Answer:
let us consider the month has 30 days
240 = 30
300= a
(240+60=300)
so following inverse proportion method
240×30 = 300×a
a= 240×30/300
a = 24
so the material will last for 24 days if the month is of 30 days.
But just in case you do not want to consider the month will have 30 days, but instead it will have x days.
then after calculating the materials will last for 0.8x days .
so you can mark it as brainlist if you are satisfied with the answer
Answered by
0
Answer:
In
30
30 days steel manufactured
=
240
=240 tonnes
Now,
60
60 more tonnes of steel is to be manufactured in that month.
So,
240
+
60
=
300
240+60=300 Tonnes of steel to be manufactured in the month.
Therefore,
More steel manufactured, less days the material will last.
This is an inverse proportion.
240
:
300
::
300
:
x
240:300::300:x
300
x
=
240.30
300x=240.30
300
x
=
7200
300x=7200
x
=
7200
/
300
x=7200/300
x
=
24
x=24
So, the material will last for
24
24 days.
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