Math, asked by anupgrg129, 8 months ago

At the beginning of a month, a factory has enough materials to make 240 tonnes of steel in a month. If 60 more tonnes of steel are to be made in that month, how long will the materials last? Is it an inverse proportion or proper proportion and How?​

Answers

Answered by vedantkawarkhe
0

Answer:

let us consider the month has 30 days

240 = 30

300= a

(240+60=300)

so following inverse proportion method

240×30 = 300×a

a= 240×30/300

a = 24

so the material will last for 24 days if the month is of 30 days.

But just in case you do not want to consider the month will have 30 days, but instead it will have x days.

then after calculating the materials will last for 0.8x days .

so you can mark it as brainlist if you are satisfied with the answer

Answered by CHATURVEDIAYUSHI789
0

Answer:

In

30

30 days steel manufactured

=

240

=240 tonnes

Now,

60

60 more tonnes of steel is to be manufactured in that month.

So,

240

+

60

=

300

240+60=300 Tonnes of steel to be manufactured in the month.

Therefore,

More steel manufactured, less days the material will last.

This is an inverse proportion.

240

:

300

::

300

:

x

240:300::300:x

300

x

=

240.30

300x=240.30

300

x

=

7200

300x=7200

x

=

7200

/

300

x=7200/300

x

=

24

x=24

So, the material will last for

24

24 days.

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