Math, asked by brijrajkumargupta101, 1 year ago

At the beginning of a war,the number of war planes possessed by two powers are in the ratio of 1.6:1 the weaker power having 400. In general engagement, each power loses the same number of planes but the ratio is changed to 2:1. How many planes does each lose.

Answers

Answered by chbilalakbar
64

Answer:

160 planes loss by both to get new ratio 2 : 1

Step-by-step explanation:

Let

First power have planes = 1.6(x)

Second power have planes = x

Then

Ratio will have be 1.6(x) : x = 1.6 : 1

Now

According to the condition

less power have planes = 400

And

Since 1.6 > 1

So

x = 400

And

Second power have planes = 1.6(400) = 640

Now

According to the second condition

If y numbers planes loss then the new ratio is 2 : 1

And

So

640 - y : 400 - y = 2 : 1

This implies that

(640 - y) / (400 - y) = 2 / 1  

This implies that

640 - y = 2( 400 - y)

640 - y = 800 - 2y

2y - y = 800 - 640

y = 160

So

160 planes loss by both to get new ratio 2 : 1

Checking:

640 - 160 = 480

400 - 160 = 240

And

480 : 240 = 480 / 240 = 2 / 1

Answered by goswamichandrakala41
4

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