At the bottom edge of a smooth wall, an inclined plane is kept at an angle of 45°. A uniform ladder of length and mass M rests on the inclined plane against the wall such that it is perpendicular to the incline. If un, is the minimum coefficient of friction with "B" necessary so that the adder does not slip on the incline. n = ?
Answers
Answer:
There are four forces acting on the ladder of length L and making ?=53
degrees with the vertical smooth wall and on a horizontal rough floor.
1. the weight W=(10×9.8) = 98 N
acting downwards through the middle of the ladder
2. vertical reaction on the floor acting upwards, equal to W.
These two forces form a couple of magnitude
W(2L)sin?
3. Normal reaction N on the wall (horizontal) at the top end of the ladder,
equal in magnitude to
4. Frictional force F acting horizontally at the bottom of the ladder.
These two forces form another couple equal to FLcos?.
Since the ladder is in equilibrium, the two couples must be equal, thus
W(2L)sin? = FLcos?
From which we can solve for F
= (2W)tan?
= (298) tan 530
= 65 N
Explanation:
HOPE IT HELPS AS SIMILAR TO YOURS QUESTION
PLEASE MARK ME AS THE BRAINLIEST
I AM YOUR FOLLOWER
Answer:
90 . digree it will be the answer