At the dog park their are several dogs with their owners. Counting heads, there are 12, counting legs, there are 38. How many dogs and owners are there?
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Let the no of owners =x
Hence no of dog= 12-x
ATQ (12-x)4 + x*2 = 38
⇒ 48 -4x +2x = 38
⇒ 2x=10 or x=5
No. of owners 5 and no. of dogs=12-5=7
Hence no of dog= 12-x
ATQ (12-x)4 + x*2 = 38
⇒ 48 -4x +2x = 38
⇒ 2x=10 or x=5
No. of owners 5 and no. of dogs=12-5=7
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