Math, asked by sunitachourasiya1983, 6 months ago

at the end of one year.
7. Find the difference between the simple interest and compound interest on 16,000 for 1
per annum, compound interest being reckoned half yearly.
interest for the first second and thir
15 years at 5%
the nomneund interest on 21
C1​

Answers

Answered by premsinghaniya12
0

Answer:

sorry I'm not sure your question

Answered by Anonymous
3

Answer:

₹ 30.25

Step-by-step explanation:

Simple Interest

P = 16000, R = 5 % and Time = 3/2 years.

Simple Interest = P*R*T/100

= (16000×5×3)/(2×100)

Simple Interest = ₹ 1200

Compound Interest

P = 16000, R = 2.5 %

(per half year Because compound interest is being reckoned half yearly and Time 3/2 years or 3 half years.)

A = P(1 +r/100)ⁿ

= 16000(1 + 2.5/100)³

= (16000×102.5×102.5×102.5) (100×100×100)

A = ₹ 17230.25

Compound Interest = 17230.25 - 16000 = ₹ 1230.25

So, the difference between the compound interest and simple interest = 1230.25 - 1200 = ₹ 30.25

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