Question

At the end of the course, a student participates in 3 exams The
passing score is 85%. All the exams have the same weightage, so
the overall score is calculated by average of their 3 scores. T

Answer 1

Answer:

$\huge \mathcal \colorbox{green}{{ \color{yellow}{❀PêRfèCt ÀnsWër}}}$

Basically, take your your percentages, in my example:

Quizes - 89%

Tests - 94%

Homework - 83%

Participation - 99%

Then your weights:

Quizes = 20%

Tests = 30%

Homework = 30%

Participation = 20%

And finally, multiply the percentages (which must be converted to decimals) by the weights and add. So:

(quiz percent*quiz weight)+(test percent*test weight)+(homework percent * homework weight)+(participation percent*participation weight)

=

(.89*.20)+(.94*.30)+(.83*.30)*(.99*.20)

= .907

Of course you can just convert this to percents, which would give you 91%.

Answer 2

Answer:

Basically, take your your percentages, in my example:

Quizes - 89%

Tests - 94%

Homework - 83%

Participation - 99%

Then your weights:

Quizes = 20%

Tests = 30%

Homework = 30%

Participation = 20%

And finally, multiply the percentages (which must be converted to decimals) by the weights and add. So:

(quiz percent*quiz weight)+(test percent*test weight)+(homework percent * homework weight)+(participation percent*participation weight)

=

(.89*.20)+(.94*.30)+(.83*.30)*(.99*.20)

= .907

Of course you can just convert this to percents, which would give you 91%.

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Explanation:

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