Question

At the equilibrium position in the process of
adsorption ................. .
(a) ∆H > 0 (b) ∆H = T∆S
(c) ∆H > T∆S (d) ∆H < T∆S

Answer 1

answer : option (b) ∆H = T∆S

at equilibrium, rate of forward reaction = rate of backward reaction. so this reason, there is no work done by the system. and hence Gibbs free energy equals to zero.

but we know, ∆G = ∆H - T∆S

where ∆G is Gibbs free energy

∆H is enthalpy change and ∆S is entropy change.

at equilibrium, ∆G = 0

so, 0 = ∆H - T∆S

⇒∆H = T∆S

hence option (b) is correct choice.

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