Question

At the height 0.4m from the ground, the velocity of projectile in vector form is; v=6i^+2j^ m/s. The angle of projection from horizontal is

Answer 1

Answer:

At a height 0.4m from the ground the velocity of a projectile in vector form is →v=(6ˆi+2ˆj)ms-1. The angle of projection is. tanθ=uyux=2√36=1√3⇒θ=30∘.

Explanation:

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