Question

At the height 8000 m, an aeroplane is moving horizontally with speed of 100 m/s. A bomb is dropped from it, so as to hit a target. At what horizontal distance from the target, should the bomb be released? (g = 10 m/s2). Pls answer this question fast. Its very urgent

Answer 1

Given:

Height at which aeroplane is flying,s= 8000 m

Initial velocity of aeroplane or bomb in horizontal direction,u= 100 m/s

To Find:

At what horizontal distance from the target, should the bomb be released

Solution:

We know that,

• Initial velocity of body dropped from height in vertical direction is 0 m/s

For vertical motion of bomb

On applying second equation of motion,we get

$\longrightarrow\rm{s=ut+\dfrac{1}{2}at^{2}}$

$\longrightarrow\rm{8000=(0)t+\dfrac{1}{2}(10)t^{2}}$

$\longrightarrow\rm{8000=5t^{2}}$

$\longrightarrow\rm{5t^{2}=8000}$

$\longrightarrow\rm{t^{2}=\dfrac{8000}{5}}$

$\longrightarrow\rm{t^{2}=1600}$

$\longrightarrow\rm{t=\sqrt{1600}}$

$\longrightarrow\rm{t=40\ s}$

And we know that, time remains same for horizontal motion also

For Horizontal motion of bomb

Here,

Speed of bomb, v= 100 m/s

Time taken by bomb to reach ground,t= 40 s

Let the distance travelled by bomb be d

So,

$\longrightarrow\rm{d=v\times t}$

$\longrightarrow\rm{d=100\times 40}$

$\longrightarrow\rm\green{d=4000\ m}$

So, bomb should be thrown 4000 m before the target in horizontal direction

Answer 2

Answer:

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