Chemistry, asked by maitreyasingh7386, 9 months ago

At the high pressure, Langmuir adsorption isotherm takes
the form
(a) x/m = ap/1 + bp
(b) x/m = a/b
(c) x/m = ap
(d) m/x = b/a = 1/ap

Answers

Answered by Anonymous
0

Answer:

At the high pressure, Langmuir adsorption isotherm takes

the form

(a) x/m = ap/1 + bp

(b) x/m = a/b

(c) x/m = ap

(d) m/x = b/a = 1/ap

Answered by techtro
0

At the high pressure, Langmuir adsorption isotherm takes the form as :

• Langmuir derived following equation on the basis of his observations.

i.e

x/m \:  =  ap/1 + bp

• Where x/m = Fraction adsorbed

p = equilibrium pressure

• We can say that,

Larger the value of a and b, more stronger would be the binding.

• When pressure is high, bp >> 1

Therefore, 1 +bp is approximately written as bp

x/m = ap/bp

x/m = a/b

• At high pressure, fraction adsorbed is independent of pressure.

• Correct option : b)

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