Question

at the position of centre of gravity 50 cm mark as shown in the figure.
Two forces, 5 N and 10 N are acting at 'O' and 'P' respectively on a uniform meter rod suspended
R
50 cm
P.
100 cm
T= woma 8007
.
=W- (80) (ro)
5 N
10 N
googoo w
What is the position of 'P' on meter rod?
A) 80 cm
B) 75 cm
C) 70 cm
D) 65 cm​

Answer 1

Answer:

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